The reading for this lecture includes the implementation
of sleep() and wakeup(), which processes
running in the kernel use to coordinate with each other. Usually one
process waits for something to happen by calling sleep(),
and another process later indicates that the event has occured by
calling wakeup(). For example, a read() on
an empty pipe involves a sleep() to wait for input; a
later write() to the pipe calls wakeup().
One problem that the sleep() and wakeup()
implementations avoid is races in which process A has decided to sleep
but has not quite gone to sleep, at which point process B calls
wakeup() but doesn't see that A is sleeping and thus does not wake A
up. If it were possible for this to occur, A would have missed the
event it was sleep()ing for, and its sleep()
might never return.
Submit:
ptable.lock help avoid this problem? Give an
ordering of events
that could result in a wakeup being missed if
the ptable.lock were not used.
You need only include the relevant lines of code.sleep is also protected by a second lock, its second argument,
which need not be the ptable.lock. Look at the example in ide.c,
which uses the idelock. Give an ordering of instructions that could
result in a wakeup being missed if the idelock were not being used.
(Hint: this should not be the same as your answer to question 1. The
two locks serve different purposes.)